Asked by LISA
i don't know which one is match. i tried those problem. i couldn't solve it
Find y' by implicit differentiation. Match the expressions defining y implicitly with the letters labeling the expressions for y'.
1. 7xsiny+2cos2y=2cosy
2. 7xcosy+2sin2y=2siny
a. 7cosy/7xsiny-4cos2y+2cosy
b. -(7siny/7xcos-4cos2y+2siny)
c. 7siny/4sin2y-xcosy-2siny
d. 7cosy/7xsiny+4sin2y+2cosy
Find y' by implicit differentiation. Match the expressions defining y implicitly with the letters labeling the expressions for y'.
1. 7xsiny+2cos2y=2cosy
2. 7xcosy+2sin2y=2siny
a. 7cosy/7xsiny-4cos2y+2cosy
b. -(7siny/7xcos-4cos2y+2siny)
c. 7siny/4sin2y-xcosy-2siny
d. 7cosy/7xsiny+4sin2y+2cosy
Answers
Answered by
Steve
1.
7xsiny+2cos2y=2cosy
7siny + 7xcosy*y' - 4sin2y*y' = -2siny*y'
y' = 7siny/(-7xcosy + 4sin2y - 2siny)
is there a typo in (b) or (c)?
2.
7xcosy+2sin2y=2siny
7cosy - 7xsiny*y' + 4cos2y*y' = 2cosy y'
y' = 7cosy/(2cosy + 7xsiny - 4cos2y)
= (a)
7xsiny+2cos2y=2cosy
7siny + 7xcosy*y' - 4sin2y*y' = -2siny*y'
y' = 7siny/(-7xcosy + 4sin2y - 2siny)
is there a typo in (b) or (c)?
2.
7xcosy+2sin2y=2siny
7cosy - 7xsiny*y' + 4cos2y*y' = 2cosy y'
y' = 7cosy/(2cosy + 7xsiny - 4cos2y)
= (a)
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