Asked by Anonymous
how many liters hydrogen if you react 3.51 L of .97M hydrochloric acid with excess zinc?
Answers
Answered by
DrBob222
Zn + 2HCl ==> ZnCl2 + H2
mols HCl = M x L = ?
From the equation, mols H2 formed is 1/2 mols HCl.
I suppose you want the volume at STP. That will be mols H2 x 22.4L/mol = ?
mols HCl = M x L = ?
From the equation, mols H2 formed is 1/2 mols HCl.
I suppose you want the volume at STP. That will be mols H2 x 22.4L/mol = ?
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