Asked by Hannah

A particular reaction has an activation energy of 51.6kJ/mol-rxn. How much faster is the reaction at 50 degrees C versus 25degrees C?

I do not know how to start this!
Answered by DrBob222
I think we've gone over this before. You start by substituting into the Arrhenius equation. Ea goes in in J/mol (not kJ/mol) and you change T to kelvin.
Answered by Hannah
So the equation I use is ln k = a + (-ea/rt) correct?
Answered by DrBob222
I would use ln(k2/k1) = (Ea/R)(1/T1 - 1/T2)
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