Asked by Hannah

For H2(g) + Br2(g) -> 2HBr(g) k=64
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Ice table:
H2 Br2 HBr
I 0.10 0.10 0
C -x -x +2x
E

Solve for HBr at equilibrium

I do not know how to start this.
Answered by Hannah
I tryed and got .20. Is this correct?
Answered by DrBob222
Where did the 1.0, 10.0 and 10.0 come from?
Answered by Hannah
Those were the values that the teacher put in there. I just assumed that since H2 and Br2 are -x and HBr is +2x that HBr would be 2 X 0.10..
Answered by DrBob222
Did the teacher put them in as initial concentrations or are they changes or equilibrium concentrations?
Answered by Hannah
He didn't say, he just posted the question like above.
Answered by DrBob222
What are you supposed to do with the numbers? What's the question?
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