Asked by Nade

A 3.00 - µF and a 4.00 - µF capacitor are connected in series, and this combination is connected in parallel with a 2.00 - µF capacitor (see the figure ). What is the net capacitance?
3.00 - µF 4.00 - µF

2.00 - µF


26.0 V
Answered by Steve
For the two caps in series, 1/C = 1/3 + 1/4
C = 12/7

For the two caps now in parallel, C = 2 + 12/7 = 26/7 = 3.71
Answered by Nade
Thank you Steve!
Answer
2.0
4th
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