Question
What mass of HNO3 is present in 248.6 mL of a nitric acid solution having a pH = 5.04?
Answers
DrBob222
Convert pH to (H^+) by
pH = -log(H^+)
Since there is 1 mol H^+ in 1 mol HNO3, then that is the concn of HNO3 in moles/L.
mols in 248.6 mL = M HNO3 x L HNO3 and g = mols x molar mass.
pH = -log(H^+)
Since there is 1 mol H^+ in 1 mol HNO3, then that is the concn of HNO3 in moles/L.
mols in 248.6 mL = M HNO3 x L HNO3 and g = mols x molar mass.