Asked by matt
When Dr. Farrell was a graduate student, he once made up a pH 8.0 sodium acetate buffer. Why would the casual observer to this buffering faux pas come to the conclusion that he had the intellectual agility of a small soap dish?
Answers
Answered by
DrBob222
Try this for size. There may be other reasons why this is not such a good buffer for pH = 8.0
pH = pKa + log (base/acid)
8.0 = 4.76 + log (base/acid)
8-4.76 = 3.24 = log (base/acid)
B/A = 1,738; therefore,
base (acetate in this case) = 1,738(A). Thus suppose we start with 1 mol acetic acid (A), then acetate mut be 1,738 mols. Could you dissolve almost 2 kmol sodium acetate (is that about 142 kg?) in 60 g acetic acid.
pH = pKa + log (base/acid)
8.0 = 4.76 + log (base/acid)
8-4.76 = 3.24 = log (base/acid)
B/A = 1,738; therefore,
base (acetate in this case) = 1,738(A). Thus suppose we start with 1 mol acetic acid (A), then acetate mut be 1,738 mols. Could you dissolve almost 2 kmol sodium acetate (is that about 142 kg?) in 60 g acetic acid.
Answered by
Anonymous
no
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