Asked by Doryn

The magnetic force on a straight wire .69 m long is 1.5 x 10^-3 N. The current in the wire is 16.9 A. What is the magnitude of the magnetic field that is perpendicular to the wire?
Answered by drwls
F = B I L

Solve for B, in units of Tesla

B = F/(L*I) = 1.5*10^-3/(0.69*16.9)
= ___ T
Answered by hope
here
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