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Given A = (X-2 1 )

2 X-3
is a singular matrix,find the value of x

1 answer

D(A) = (x-2)(x-3) - 2
a singular matrix has 0 determinant.
x^2 - 5x + 6 - 2 = 0
x^2 - 5x + 4 = 0
(x-1)(x-4) = 0

x = 1 or 4

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