Asked by Matt

[H^+] = 2.7 x 10^-3

Calculate for [OH^-]
[OH^-] = ? M

13 years ago

Answered by DrBob222

I do these by calculating pOH = -log(OH^-), then subtracting from 14.
pH + pOH = pKw = 14

13 years ago

Answered by Anonymous

The other way is [H^+]*[OH^-] = 10^-14

13 years ago

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