Asked by hall

if the activation energy for a given compound is found to be 10 kJ/mol, with a frequency factor of 4.0x10^13 s-1, what is the rate constant for this reaction at 398K?

Answers

Answered by DrBob222
k = Ae<sup>(-E<sup>a</sup>/RT)</sup>
You can read more about it here.
http://en.wikipedia.org/wiki/Arrhenius_equation
Answered by DrBob222
I should have written E<sup>a</sup> as E<sub>a</sub>. Ea is the activation energy.
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