Asked by Bongo
Calculate the force of gravity between a 2.50 kg newborn baby and a 80.0 kg doctor standing 0.250 m away. G = 6.67 E -11 N*m2/kg2
My work
Fg = (Gm1 Gm2) /d^2
m1=2.50 kg
m2=80.0 kg
d=0.250 m
g=6.67 E -11 N*m2/kg2
Fg = (Gm1 Gm2) /d^2
Fg= g ( 2.50 kg)(80.0 kg)/0.250m^2
Fg= (6.67 E -11 N*m2/kg2)( 2.50 kg)(80.0 kg)/0.250m^2
Fg=
I keep messing up at the end i cant get the right answer. I just needto know how to multiply that last part, im getting confused with the gravity part of it...
My work
Fg = (Gm1 Gm2) /d^2
m1=2.50 kg
m2=80.0 kg
d=0.250 m
g=6.67 E -11 N*m2/kg2
Fg = (Gm1 Gm2) /d^2
Fg= g ( 2.50 kg)(80.0 kg)/0.250m^2
Fg= (6.67 E -11 N*m2/kg2)( 2.50 kg)(80.0 kg)/0.250m^2
Fg=
I keep messing up at the end i cant get the right answer. I just needto know how to multiply that last part, im getting confused with the gravity part of it...
Answers
Answered by
drwls
You have all the numbers correct in the formula, so all you have to do is make the calculation. Having 0.250^2 (which is 1/16) in the denominator is the same as multiplying by 16.
I get 2.13*10^-7 Newtons for the answer. All of the other dimensions cancel (kg and m) out
I get 2.13*10^-7 Newtons for the answer. All of the other dimensions cancel (kg and m) out
Answered by
drwls
I had the advantage of using a hand calculator with scientific notation. I'm lazy.
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