Asked by Tati
If you have a 12.01g sample carbon. What would be the average mass of a carbon atoms if it is 1.994 x 10 to the 23 power g. How many carbon atoms are in the sample?
Answers
Answered by
bobpursley
Numberatoms=masssample/massoneatom
Answered by
drwls
Your question is unclear. The mass cannot be both 12.01 g and 1.994*10^23 g.
A 12.01 g sample of C is one mole, and therefore contains Avogadro's nunber of atoms, which is 6.02*10^23 atoms
The average mass of a C atom is
(12.01 g)/(6.02*10^23 atoms)
They all have the same mass, except for about 1% that are Carbon-13 isotope)
A 12.01 g sample of C is one mole, and therefore contains Avogadro's nunber of atoms, which is 6.02*10^23 atoms
The average mass of a C atom is
(12.01 g)/(6.02*10^23 atoms)
They all have the same mass, except for about 1% that are Carbon-13 isotope)
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