Asked by sage

A 0.85 g sample of solute with a molecular mass of 185 g/mol is dissolved in 2.25 g of benzene. What is the expected boiling point of the solution?
Answered by DrBob222
moles solute = grams/molar mass.
Substitute and solve for moles.

m = mols/kg solvent
Substitute and solve for m

delta T = Kf*m
Substitute and solve for delta T, then
subtract delta T from 0 C to find the new freezing point. This is what you would expect for a non-ionizable solute. The problem doesn't say.
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