Asked by Rob
A box which has a mass of 14kg is sliding along a horizontal surface with a velocity of 18m/s when it encounters a frictionless inclined plane which meets the horizontal at an angle of 28 degrees. The box slides up the incline until it comes to a halt.
How far up the incline will the box slide before it stops? (35.2m)
How far up the incline will the box slide before it stops? (35.2m)
Answers
Answered by
bobpursley
its initial KE= final PE
1/2 m v^2= mgh=mg*distance*sin28
solve for distance.
1/2 m v^2= mgh=mg*distance*sin28
solve for distance.
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