I had to perform an experiment for rate of reaction.
I have to calculate the concentration of Na2S2O3 in the reaction solutions based on the volume used in each reaction flask and the total volume calculated.
There were five flasks used and for all 5 of them 2.50mL of Na2S2O3 was used and the total volume for all 5 combined was 15mL. Do I just multiply both of these? 2.50mL X 15mL = 37.5 mL
2 answers
I'm unsure of what you did but adding all of the volumes together surely isn't what you are to do.The concn of EACH flask will be (initial concn) x (2.50mL/final volume in each flask). Since the initial concn is the same for all, then 2.50/final volume for each flask will give you a relative molarity. Perhaps that's what you are to do. You have provided too few details for me to be sure.
Im sorry. The point of the experiment was to show how changes in reactant concentration, temperature, and catalyst presence can affect the rate of a reaction. The reaction that we studied was
H2O2 + 2I^- + 2H^+ -> I2 + 2H2O
We had to set up 6 flasks each with and certain amount of KI, starch, DI water, buffer, acid, Na2S2O3, and H2O2 all in mL. Then we had to measure the time it took for a reaction to happen which was indictated when the solution began to turn blue. For Na2S2O3 each flask had 2.50mL in it which is a total of 15.
H2O2 + 2I^- + 2H^+ -> I2 + 2H2O
We had to set up 6 flasks each with and certain amount of KI, starch, DI water, buffer, acid, Na2S2O3, and H2O2 all in mL. Then we had to measure the time it took for a reaction to happen which was indictated when the solution began to turn blue. For Na2S2O3 each flask had 2.50mL in it which is a total of 15.
6 answers