Asked by Brianna
What is the [H3O] concentration in a 1.0M CH3COONa solution? (The Ka for CH3COONa is 2.0*10-5.)
Answers
Answered by
DrBob222
The pH is determined by the hydrolysis of the salt. Let Ac = acetate; HAc = acetic acid
.........Ac^- + HOH ==> HAc +OH^-
initial...1M.............0....0
change....-x.............x.....x
equil....1-x.............x.....x
Kb for Ac^- = (Kw/Ka for HAc) = (HAc)(OH^-)/(Ac^-)
Substitute from the ICE chart and solve for x, convert to (H^+).
.........Ac^- + HOH ==> HAc +OH^-
initial...1M.............0....0
change....-x.............x.....x
equil....1-x.............x.....x
Kb for Ac^- = (Kw/Ka for HAc) = (HAc)(OH^-)/(Ac^-)
Substitute from the ICE chart and solve for x, convert to (H^+).
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