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Asked by Harley

sin(x) = 8/17 and 90 degrees < x < 180 degrees then find cos2(x)
13 years ago

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Answered by MathMate
Use sin²(x)+cos²(x)=1
and the fact that cos(x) in the second quadrant is negative does not change the value of cos²(x).
13 years ago
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sin(x) = 8/17 and 90 degrees < x < 180 degrees then find cos2(x)

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