Asked by Anonymous
I need help solve the equation by fractions
8/(21-y) = 12/(y+19)
I think the answer is y = 5, i just need to know how to do work out. i done some solution like this
first multiply by(21-y)(y+19)(assuming that y = 21 and y = 19:
(21-y)(y+19)8/(21-y) = (21-y)(y+19)12/(y+19)
then cancel and multiply out the brackets:
8(y+19) = 12(21-y)
that is
8x+152 = 12x-96
finally,rearrange the equation as
160x = 104
8/(21-y) = 12/(y+19)
I think the answer is y = 5, i just need to know how to do work out. i done some solution like this
first multiply by(21-y)(y+19)(assuming that y = 21 and y = 19:
(21-y)(y+19)8/(21-y) = (21-y)(y+19)12/(y+19)
then cancel and multiply out the brackets:
8(y+19) = 12(21-y)
that is
8x+152 = 12x-96
finally,rearrange the equation as
160x = 104
Answers
Answered by
MathMate
y=5 is correct.
To multiply by (21-y)(y+19), y must <i>not</i> equal 21 nor -19.
Correct until
8(y+19) = 12(21-y)
Expand:
8y+152=-12y+252
20y=100
y=5
To multiply by (21-y)(y+19), y must <i>not</i> equal 21 nor -19.
Correct until
8(y+19) = 12(21-y)
Expand:
8y+152=-12y+252
20y=100
y=5
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