Question
Liquid Butane, C4H10, is stored in cylinders to be used as a fuel. Suppose 39.3g of butane gas is removed from a cylinder. How much heat must be provided to vaporize this much gas? The heat of vaporization of butane is 21.3 kJ/mol.
Answers
39.3 g butane* 21.3 kJ/mol = ??,
Convert 39.3 g butane to mols and use the above equation.
Convert 39.3 g butane to mols and use the above equation.
yes
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