Can't you figure it out from my previous answer?
http://www.jiskha.com/display.cgi?id=1329965056
http://www.jiskha.com/display.cgi?id=1329965056
Sam spent a total of 5 2/3 hours on homework. We can convert this mixed number to an improper fraction by multiplying the whole number (5) by the denominator (3) and adding it to the numerator (2). The result is 17/3.
Julia spent 5 5/6 hours on homework. To convert this mixed number to an improper fraction, we multiply the whole number (5) by the denominator (6) and add it to the numerator (5). The result is 35/6.
Now that we have both times in fractions, we can compare them directly. We see that Sam spent 17/3 hours, while Julia spent 35/6 hours on homework.
To compare fractions, we can find a common denominator, so we can compare numerators directly. The least common multiple (LCM) of 3 and 6 is 6. So, we can rewrite 17/3 as 34/6 (multiply the numerator and denominator by 2) and compare it to 35/6.
Now it is clear that 35/6 (Julia's time) is greater than 34/6 (Sam's time).
Therefore, Julia spent more time on homework this week than Sam.