Asked by krystal
If 19.7 g of CaCl2 are present in 200 mL of aqueous solution, what is the concentration in terms of the following?
a. molarity
100 M CaCl2
b. weight/volume percent
0.1 % (w/v)
c. parts per thousand
100 ppt
d. parts per million
10E4 ppm
e. parts per billion
10E7 ppb
a. molarity
100 M CaCl2
b. weight/volume percent
0.1 % (w/v)
c. parts per thousand
100 ppt
d. parts per million
10E4 ppm
e. parts per billion
10E7 ppb
Answers
Answered by
DrBob222
a)
19.7g CaCl2/111 = 0.177 moles
0.177 mol/0.200L = ?
b)
19.75g/200 mL = how much per 100, so 1/2 x 19.76 = ?
c) etc
19.7g CaCl2/111 = 0.177 moles
0.177 mol/0.200L = ?
b)
19.75g/200 mL = how much per 100, so 1/2 x 19.76 = ?
c) etc
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.