Asked by Lauren01
A train moving at a constant speed on a surface inclined upward at 10.0° with the horizontal travels a distance of 400 meters in 5 seconds. Calculate the vertical velocity component of the train during this time period.
Answers
Answered by
Damon
Goes up distance 400 sin 10 = 69.5 m
69.5 m/ 5 s = 13.9 m/s up
69.5 m/ 5 s = 13.9 m/s up
Answered by
Anonymous
A train moving at a constant speed on a surface inclined upward at 10.0° with the horizontal travels a distance of 400 meters in 5 seconds. Calculate the vertical velocity component of the train during this time period
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