Asked by Kevin
How to Generate Pythagorean Triples using an Odd Number
1. Start with an odd number, e.g. 3. Then the square of 3 can be expressed as the sum of two consecutive numbers, i.e. 32 = 9 = 4 + 5. Therefore the Pythagorean Triples are {3, 4, 5} since 32 + 42 = 52. Generate another set of Pythagorean Triples starting with the next odd number 5 and verify that it works.
2. Generate another set of Pythagorean Triples starting with the next odd number 7 and verify that it works.
3. Prove that this method will always work for any odd number except 1.
1. Start with an odd number, e.g. 3. Then the square of 3 can be expressed as the sum of two consecutive numbers, i.e. 32 = 9 = 4 + 5. Therefore the Pythagorean Triples are {3, 4, 5} since 32 + 42 = 52. Generate another set of Pythagorean Triples starting with the next odd number 5 and verify that it works.
2. Generate another set of Pythagorean Triples starting with the next odd number 7 and verify that it works.
3. Prove that this method will always work for any odd number except 1.
Answers
Answered by
Damon
please write exponent with ^ symbol
3^2 = 9
5, ?
25 = sum of 12 and 13
25 + 144 = 169 ?
yes
so 5, 12, 13 works
x^2 = n + (n+1)
is x^2 + n^2 = (n+1)^2 ???
x^2 + n^2 = n^2 +2 n + 1 ???
so if x^2 = 2 n + 1 we have it
but we see 2 n + 1 = n + (n+1)
so true
but what if n is even
try x = 2
x^2 = 4
BUT 4, an even number can not be made from the sum of two consecutive whole numbers. So x must be odd.
3^2 = 9
5, ?
25 = sum of 12 and 13
25 + 144 = 169 ?
yes
so 5, 12, 13 works
x^2 = n + (n+1)
is x^2 + n^2 = (n+1)^2 ???
x^2 + n^2 = n^2 +2 n + 1 ???
so if x^2 = 2 n + 1 we have it
but we see 2 n + 1 = n + (n+1)
so true
but what if n is even
try x = 2
x^2 = 4
BUT 4, an even number can not be made from the sum of two consecutive whole numbers. So x must be odd.
There are no AI answers yet. The ability to request AI answers is coming soon!