Asked by Scott
In a triangle the two larger angles differ by 10 degree. The smaller angle is 50 degree less than the largest angle. Find the measure of each angle. Just searching help on how to set it up.
Answers
Answered by
Anonymous
A , B and C = The angles of a triangle
A = The largest angle
C = The smaller angle
B = A - 10 °
C = A - 50 °
The angles of a triangle always sum to 180 °
A + B + C = 180 °
A + A - 10 ° + A - 50 ° = 180 °
3 A - 60 ° = 180 °
3 A = 180 ° + 60 °
3 A = 240 ° Divide both sides by 3
A = 240 ° / 3
A = 80 °
B = A - 10 °
B = 80 ° - 10 °
B = 70 °
C = A - 50 °
C = 80 ° - 50 °
C = 30 °
A = The largest angle
C = The smaller angle
B = A - 10 °
C = A - 50 °
The angles of a triangle always sum to 180 °
A + B + C = 180 °
A + A - 10 ° + A - 50 ° = 180 °
3 A - 60 ° = 180 °
3 A = 180 ° + 60 °
3 A = 240 ° Divide both sides by 3
A = 240 ° / 3
A = 80 °
B = A - 10 °
B = 80 ° - 10 °
B = 70 °
C = A - 50 °
C = 80 ° - 50 °
C = 30 °
Answered by
ANNETTE
IN A TRIANGLE THE TWO LARGER ANGLES DIFFER BY 10 DEGREE. tHE SMALLER ANGLE 50 DEGREE LESS THAN THE LARGEST ANGLE. WHAT IS THE MEASURE
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