Question
A reguluation racquetball court should have a perimeter of 120 ft, with a length that is twice the width find the length and the width of a court
Answers
Anonymous
W = Width
L = Length
P = Perimeter
L = 2 W
P = 2 L + 2 W = 120 ft
2 * 2 W + 2 W = 120
4 W + 2 W = 120
6 W = 120 Divide both sides by 6
W = 120 / 6
W = 20 ft
L = 2 W
L = 2 * 20
L = 40 ft
L = Length
P = Perimeter
L = 2 W
P = 2 L + 2 W = 120 ft
2 * 2 W + 2 W = 120
4 W + 2 W = 120
6 W = 120 Divide both sides by 6
W = 120 / 6
W = 20 ft
L = 2 W
L = 2 * 20
L = 40 ft