Asked by Anonymous

A piece of copper wire of resistance R is cut into 10 equal lengths. These parts are connected in parallel. How does the joint resistance of the parallel combination compare with the original resistance of the single wire?
Answered by Tim
No drop
Answered by Memoona kousar
If all these parts are connected in parallel, that would mean the new total resistance R" can be found as follows:
1/R" = n^2/R
R" = R/n^2
R" = R/10^2
R"= 0.01