A piece of copper wire of resistance R is cut into 10 equal lengths. These parts are connected in parallel. How does the joint resistance of the parallel combination compare with the original resistance of the single wire?
2 answers
No drop
If all these parts are connected in parallel, that would mean the new total resistance R" can be found as follows:
1/R" = n^2/R
R" = R/n^2
R" = R/10^2
R"= 0.01
1/R" = n^2/R
R" = R/n^2
R" = R/10^2
R"= 0.01
1 answer