Asked by Jay C
3-square root 2/ 1+square root 2
Answers
Answered by
drwls
This is not trig.
(3 - sqrt2)/(1 + sqrt2)
= (3-sqrt2)(1-sqrt2)/[(1-sqrt2)(1+sqrt2)]
= [3 - 4sqrt2 +2]/(1-2)
= (5 -4sqrt2)/-1
= 4sqrt2 -5
(3 - sqrt2)/(1 + sqrt2)
= (3-sqrt2)(1-sqrt2)/[(1-sqrt2)(1+sqrt2)]
= [3 - 4sqrt2 +2]/(1-2)
= (5 -4sqrt2)/-1
= 4sqrt2 -5
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