Asked by Heather
A 50/50 blend of engine coolant and water (by volume) is usually used in an automobile\'s engine cooling system. If your car\'s cooling system holds 4.90 gallons, what is the boiling point of the solution? Make the following assumptions in your calculation; at normal filling conditions, the densities of engine coolant and water are 1.11 g/mL and 0.998 g/mL respectively. Assume that the engine coolant is pure ethylene glycol (HOCH2CH2OH), which is non-ionizing and non-volatile, and that the pressure remains constant at 1.00 atm.
Answers
Answered by
DrBob222
Convert 4.90 gallons to liters.
1/2 of that will be glycol; 1/2 will be water.
Using density, convert L H2O to grams and L glycol to grams.
Convert grams glycol to moles. moles = grams/molar mass
Convert moles glycol to molality. m = moles/kg solvent
Then delta T= Kb*m
Solve for delta T and add to 100 C to find the new boiling point.
1/2 of that will be glycol; 1/2 will be water.
Using density, convert L H2O to grams and L glycol to grams.
Convert grams glycol to moles. moles = grams/molar mass
Convert moles glycol to molality. m = moles/kg solvent
Then delta T= Kb*m
Solve for delta T and add to 100 C to find the new boiling point.
Answered by
shsn
34
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.