Asked by Heather
Express the concentration of a 0.0860 M aqueous solution of fluoride, F–, in mass percentage and in parts per million. Assume the density of the solution is 1.00 g/mL.
Answers
Answered by
DrBob222
0.0860M F^- = 0.0860 mols/L soln.
How many g is 0.0860 mols F^-? That is 0.0860 x atomic mass F = approximately 1.6 g but you need to do it more accurately.
If the L of solution has a mass of 1000 g, then the %by mass = (mass F^-/mass soln)*100 = ?
Then convert to mg/L to find ppm.
How many g is 0.0860 mols F^-? That is 0.0860 x atomic mass F = approximately 1.6 g but you need to do it more accurately.
If the L of solution has a mass of 1000 g, then the %by mass = (mass F^-/mass soln)*100 = ?
Then convert to mg/L to find ppm.
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