Asked by Lilly
At the bow of a ship on a stormy sea, a crewman conducts an experiment by standing on a bathroom scale. In calm waters, the scale reads 172 lb. During the storm, the crewman finds a maximum reading of 215 lb and a minimum reading of 131 lb. Calculate the maximum upward and downward acceleration experienced by the crewman.
Answers
Answered by
drwls
The man's mass is
M = 172/g = 5.34 slugs
The mass does not change with acceleration
Maximum upward acceleration "a" occurs when
M(a + g) = 215 lb
a + g = 215/172 = 40.3 ft/s^2
a = 40.3 - 32.2 = 8.1 ft/s^2
Maximum downward acceleration " a' " occurs when
M(g - a') = 131
g - a' = 24.5 ft/s^2
a' = 37.7 ft/s^2
M = 172/g = 5.34 slugs
The mass does not change with acceleration
Maximum upward acceleration "a" occurs when
M(a + g) = 215 lb
a + g = 215/172 = 40.3 ft/s^2
a = 40.3 - 32.2 = 8.1 ft/s^2
Maximum downward acceleration " a' " occurs when
M(g - a') = 131
g - a' = 24.5 ft/s^2
a' = 37.7 ft/s^2
Answered by
Anonymous
your answer is not right
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.