Asked by victoria
If g'(x)=2g(x) and g(-1)=1, then g(x)=
a)e^2x
b)e^-x
c)e^(x+1)
d)e^(2x+2)
e)e^(2x-2)
a)e^2x
b)e^-x
c)e^(x+1)
d)e^(2x+2)
e)e^(2x-2)
Answers
Answered by
drwls
Differentiate each choice and you will see than three (a,d,e) equal 2*g. Only one of those three satisfy
g(-1) = 1, however.
g(-1) = 1, however.
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