Asked by Billy
if g(x) varies exponentially with x, and g(0) =37 and g(7) =5940 find the particular equation...
Answers
Answered by
Steve
g = ka^x
37 = ka^0 = k
so, g = 37a^x
5940 = 37a^7
160.54 = a^7
a = 2.066
g = 37*2.066^x
37 = ka^0 = k
so, g = 37a^x
5940 = 37a^7
160.54 = a^7
a = 2.066
g = 37*2.066^x
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