When a student plotted ln [vapor pressure of a gas] vs. inverse Kelvin temperature, she obtained a straight line with a slope equal to -8.000 x 10^3 K.
According to the Clausius Clapeyron equation, Hvap is ? KJ/mol
2 answers
http://www.tau.ac.il/~phchlab/experiments/iodine/clauclap.html
This is the equation ln(P2/P1) = -DHvap/R * (1/T2- 1/T1)
but how do i get the pressure values and tempature values?
but how do i get the pressure values and tempature values?