Asked by GRISSELL
A man and a woman are walking across soft ground. The woman wears stilettos; each heel has a cross-sectional area of 0.95cm^2 (0.000095m^2) The man wears a flat shoe with a heel area of 110cm^2 (or 0.011m^2)
1. If the woman weighs 520 Newtons, how much pressure does she exerts on the ground beneath her?
p=f/a=520N/.000095m^2=5473684.211 N/m^2 Is this correct?
2. What would the man's weight need to be for him to exert an equal pressure? Don't know how to figure this one out?
1. If the woman weighs 520 Newtons, how much pressure does she exerts on the ground beneath her?
p=f/a=520N/.000095m^2=5473684.211 N/m^2 Is this correct?
2. What would the man's weight need to be for him to exert an equal pressure? Don't know how to figure this one out?
Answers
Answered by
Damon
check on part 1
2.
W/A = p
W = .011 * 5473684
= 60210 N
Huge because the pressure from the stiletto was huge.
2.
W/A = p
W = .011 * 5473684
= 60210 N
Huge because the pressure from the stiletto was huge.
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