Asked by chrystabelle
If f(x)=x-1/2x^2-x-3.Find
(i)f(2)
(ii)x if f(x)= 0
(i)f(2)
(ii)x if f(x)= 0
Answers
Answered by
Jai
f(x) = (x-1)/(2x^2) - (x-3)
#1.
f(2) = (2-1)/(2*2^2) - (2-3)
f(2) = 1/(8) - (-1)
f(2) = 1/8 + 1
f(2) = 9/8
#2.
f(x) = (x-1)/(2x^2) - (x-3)
0 = (x-1)/(2x^2) - (x-3)
x - 3 = (x-1)/(2x^2)
(2x^2)(x-3) = x - 1
2x^3 - 6x^2 - x + 1 = 0
x = -0.459
x = 0.350
x = 3.11
#3.
domain is all real numbers except zero.
#1.
f(2) = (2-1)/(2*2^2) - (2-3)
f(2) = 1/(8) - (-1)
f(2) = 1/8 + 1
f(2) = 9/8
#2.
f(x) = (x-1)/(2x^2) - (x-3)
0 = (x-1)/(2x^2) - (x-3)
x - 3 = (x-1)/(2x^2)
(2x^2)(x-3) = x - 1
2x^3 - 6x^2 - x + 1 = 0
x = -0.459
x = 0.350
x = 3.11
#3.
domain is all real numbers except zero.
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