680 ÷ 5 = (1 point) using 5th grade box method

Answer 1

To solve 680 ÷ 5 using the 5th grade box method, you would set up a long division problem. Here is an example of how you could set it up:

136
–––––––
5) 680

You would then divide the numbers one digit at a time, starting with the leftmost digit (6).

Answer 2

explain it more

Answer 3

Sure! The box method is a method of long division that helps to visually organize the steps of the division process. To illustrate how to use the box method to solve 680 ÷ 5, follow these steps:

Step 1: Set up the division problem. Write the dividend (680) inside a long division bracket. Write the divisor (5) outside of the bracket on the left side.

5) │ 680

Step 2: Analyze the first digit of the dividend. In this case, the first digit is 6. Ask yourself, how many times does 5 go into 6? The answer is 1.

1
________
5) │ 680

Step 3: Multiply the quotient (1) by the divisor (5), and write the product underneath the dividend.

1
________
5) │ 680
-5

Step 4: Subtract the product from the first set of digits in the dividend (680 - 5).

1
________
5) │ 680
-5
-----
18

Step 5: Bring down the next digit from the dividend (in this case, the second digit is 8), to create a new dividend (18).

1
________
5) │ 680
-5
-----
18

8

Step 6: Analyze the new dividend (18). Ask yourself, how many times does 5 go into 18? The answer is 3.

1
________
5) │ 680
-5
-----
18
-15

3

Step 7: Multiply the new quotient (3) by the divisor (5), and write the product underneath the new dividend (18).

1
________
5) │ 680
-5
-----
18
-15
-----
3

Step 8: Subtract the product from the new dividend (18 - 15).

1
________
5) │ 680
-5
-----
18
-15
-----
3

Step 9: There are no more digits in the dividend to bring down, so the division process ends.

Result: The quotient is 136.

So, 680 ÷ 5 = 136.

Answer 4

explain the last one more better

Answer 5

Certainly! Let me explain Step 8 in more detail.

Step 8: Subtract the product from the new dividend (18 - 15).

In this step, we're subtracting the product of the quotient (3) and the divisor (5) from the new dividend (18). This is done to calculate the remainder and determine if there are any more digits to bring down.

Here's the calculation:

1
________
5) │ 680
-5
-----
18
-15
-----
3

Subtracting 15 from 18, we get a remainder of 3.

Now, since there are no more digits to bring down from the original dividend of 680, the division process ends. The quotient obtained so far is 136 (1 brought down from the initial dividend, and 3 from the subsequent iterations).

Thus, 680 ÷ 5 = 136, with a remainder of 3.