Asked by tori
On a map, Town A is 8 km due south of Town B, Town C is 9 km from Town A, and Town C is 3 km from Town B (see figure below). Find the bearing from Town A to Town C and the bearing from Town B to Town C.
Answers
Answered by
yoyoma
Hello, there is no figure but I shall try my best to figure it out.
I think this is probably a triangle.
B
| C
| /
| /
A
AB= 8
AC=9
BC=3
A is 9 km SW of C and B is 3 km NW of C. I hope this helps.
I think this is probably a triangle.
B
| C
| /
| /
A
AB= 8
AC=9
BC=3
A is 9 km SW of C and B is 3 km NW of C. I hope this helps.
Answered by
tori
Thank you a ton!!
Answered by
yoyoma
No problem!
Answered by
Steve
To find the actual bearings, find the angles A,B,C, using the law of cosines. For example,
BC<sup>2</sup> = AB<sup>2</sup> + AC<sup>2</sup> - 2*AB*AC*cosA
9 = 64 + 81 - 144cosA
cosA = 136/144
A = 19ยบ
BC<sup>2</sup> = AB<sup>2</sup> + AC<sup>2</sup> - 2*AB*AC*cosA
9 = 64 + 81 - 144cosA
cosA = 136/144
A = 19ยบ
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