Question
A mass of 0.40 kg is attached to a spring and
is set into vibration with a period of 0.15 s.
What is the spring constant of the spring?
Answer in units of N/m
what is the rearranged equation to get for k?
is set into vibration with a period of 0.15 s.
What is the spring constant of the spring?
Answer in units of N/m
what is the rearranged equation to get for k?
Answers
The period is P = 2*pi*sqrt(m/k)
You know m.
Solve for k.
[P/(2 pi)]^2 = P^2/(4*pi^2) = m/k
You know m.
Solve for k.
[P/(2 pi)]^2 = P^2/(4*pi^2) = m/k
i go it wrong
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