See the equation in the problem.
How many moles H^+ have you added? That is M H^+ x L H^+ = moles H^+ = 1.00M x 1 L= 1.0 mol H^+.
Using the coefficients in the balanced equation, convert moles H^+ to moles PbCO3.
mols PbCO3 = moles H^+ x (1 mole PbCO3/2 mol H^+) = moles H^+ x 1/2 = 1 x 1/2 = 0.5 mol PbCO3.
Now convert mol PbCO3 to grams. g = moles x molar mass
Here is a worked example that will solve all of your stoichiometry problems. Print it out and keep it.
http://www.jiskha.com/science/chemistry/stoichiometry.html
Given the following equation, how many grams of PbCO3 will dissolve when exactly 1.0 L of 1.00 M H+ is added to 6.00 g of PbCO3?
When the equation is PbCO3(s) + 2H(+)(aq) = Pb(2+)(aq) + H2O(l) + CO2(g)
Please explain in detail, step by step
2 answers
4.6