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if dy/dx= (1+lnx)y and if y=1 when x=1, then y=
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dy/dx= (1+lnx)y --->
dy/y = (1 + ln(x)) dx --->
ln(y) = x ln(x) + c
Boundary condition:
y=1 when x=1 ---> c = 0
y = exp(x ln(x)) = x^x
dy/y = (1 + ln(x)) dx --->
ln(y) = x ln(x) + c
Boundary condition:
y=1 when x=1 ---> c = 0
y = exp(x ln(x)) = x^x
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