Asked by mouse
solve this equation by using the quadratic (3x)^2-12(3x)+27=0
Answers
Answered by
Damon
Let z = 3 x
then
z^2 -12 z + 27 = 0
(z-3)(z-9) = 0
z = 3 or z = 9
if z = 3, then x = 1
if z = 9, then x = 3
then
z^2 -12 z + 27 = 0
(z-3)(z-9) = 0
z = 3 or z = 9
if z = 3, then x = 1
if z = 9, then x = 3
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