Asked by victor.m
A telescope has an object whose focal length is 60cm.
(a)The telescope is used to watch a young zebra 500m away.If the image of the zebra is 20mm long and is located 25cm infront of the eye piece,find the actual length of the zebra
(a)The telescope is used to watch a young zebra 500m away.If the image of the zebra is 20mm long and is located 25cm infront of the eye piece,find the actual length of the zebra
Answers
Answered by
drwls
I am pretty sure that you have incorrectly typed "object" where you should have typed "objective" (lens or mirror.)
The distance x from objective to first image (formed by the objective) is given by
1/500 + 1/x = 1/f = 1/0.6
1/x = 1.665
x = 0.6007 m
Magnification = x/500 = 1.201*10^-3
(i.e, it is smaller than the actual zebra)
Zebra length = 0.020 m/1.201*10^-3
= 1.665 m
The information about the image distance from the eyepiece was not needed.
The distance x from objective to first image (formed by the objective) is given by
1/500 + 1/x = 1/f = 1/0.6
1/x = 1.665
x = 0.6007 m
Magnification = x/500 = 1.201*10^-3
(i.e, it is smaller than the actual zebra)
Zebra length = 0.020 m/1.201*10^-3
= 1.665 m
The information about the image distance from the eyepiece was not needed.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.