a 100 mL {100 grams} of water at 4.0 degrees celsius is heated until its tempurture is 37 degrees celcus. if the specific heat of water is 4.18 joules/grams degrees celcus calculate the amount of heat energy needed to cause this rise in tempurture

Question

a 100 mL {100 grams} of water at 4.0 degrees celsius is heated until its tempurture is 37 degrees celcus. if the specific heat of water is 4.18 joules/grams degrees celcus calculate the amount of heat energy needed to cause this rise in tempurture

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2 answers
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Answer 1

Explain Bot answered
1 year ago

To calculate the amount of heat energy needed to cause the rise in temperature, we will use the formula:

Q = m * c * ΔT

Where:
Q is the heat energy (in joules)
m is the mass of the water (in grams)
c is the specific heat capacity of water (in joules/gram°C)
ΔT is the change in temperature (in °C)

In this case:
m = 100 grams
c = 4.18 joules/gram°C
ΔT = 37°C - 4°C = 33°C

Now, we can plug these values into the formula to calculate the heat energy:

Q = 100 grams * 4.18 joules/gram°C * 33°C
Q = 13827 joules

Therefore, the amount of heat energy needed to raise the temperature of 100 grams of water from 4.0°C to 37.0°C is 13,827 joules.

Answer 2

Step-by-Step Bot answered
1 year ago

To calculate the amount of heat energy needed to cause the rise in temperature, you can use the formula:

Q = m * c * ΔT

where:
Q = heat energy (in joules)
m = mass of water (in grams)
c = specific heat of water (in joules/gram°C)
ΔT = change in temperature (in °C)

Given:
m = 100 grams
c = 4.18 joules/gram°C
ΔT = 37°C - 4.0°C

Substituting the values into the formula, we have:
Q = 100 grams * 4.18 joules/gram°C * (37°C - 4.0°C)

Q = 100 grams * 4.18 joules/gram°C * 33°C

Q = 138174 joules

Therefore, the amount of heat energy needed to cause the rise in temperature is 138174 joules.