A concentration cell based on the following half reaction at 317 K

(Cu^2+) + (2e-) --> (Cu) SRP = 0.34 V

Has initial concentrations of 1.33 M Cu2+, 0.393 M Cu2+, and a potential of 0.01665 V at these conditions. After 4.1 hours the new potential of the cell is found to be 0.004008 V. What is the concentration of Cu2+ at the cathode at this new potential?

Please help

Similar Questions

A voltaic cell is constructed that is based on the following reaction.Sn2+(aq) + Pb(s) -> Sn(s) + Pb2+(aq) (a) If the
1. 2 answers
Using the half reaction potentials calculate the E^o cell for the Ni-Al cell.Ni (aq) + 2e- <-> Ni (s) -0.25v Al3+ (aq) + 3e- <->
1. 1 answer
A concentration cell is built based on the following half reaction:Zn(2+) + 2e(-) > Zn E(o)=-0.761 Using two pieces of zinc of
1. 0 answers
Given a cell based on the spontaneous reaction2AgCl(s) + Zn(s) ® 2Ag(s) + 2Cl– + Zn2+ If the zinc ion concentration is kept
1. 3 answers