Question

Evaluate the following expression:
d/dx (integration sign: upper=1 and lower= -3) (2t^3 + 3)dt =
I am given the following options:
2t^3 + 3
56
5
-28.0
None of the above

Answer 1

56

Answer 2

Actually none of the above

Answer 3

∫(2t^3 + 3) dt for t=-3 to 1
= [ (1/2)t^4 + 3t] from -3 to 1
= (1/2)(1) + 3 - ( (1/2)(81) -9)
= 1/2 - 81/2 + 12
= -40 + 12
= -28