Asked by Jovante
y=cos(square root of 4t+12)
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Answered by
IVR
dy/dt=-sin(square root of 4t+12)*d/dx(sqare root of 4t+12)
=-sin(sqare root of 4t+12)*1/2*sqare root of 4t+12 * 4
=-sin (sqare root of 4t+12)* 2/sqare root of 4t+12
=-sin(sqare root of 4t+12)*1/2*sqare root of 4t+12 * 4
=-sin (sqare root of 4t+12)* 2/sqare root of 4t+12
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