Asked by Anonymous
The bongo family has three children, including a pair of twins. The third child is 3 years younger then the twins. The sum of the three ages is 42. How old is each child?
Answers
Answered by
Bosnian
a = age of the twins
b = age of the third child
b = a - 3
a + a + b = 42
2 a + b = 42
2 a + a - 3 = 42
3 a - 3 = 42
3 a = 42 + 3
3 a = 45 Divide both sides by 3
a = 45 / 3
a = 15
b = 15 - 3
b = 12
b = age of the third child
b = a - 3
a + a + b = 42
2 a + b = 42
2 a + a - 3 = 42
3 a - 3 = 42
3 a = 42 + 3
3 a = 45 Divide both sides by 3
a = 45 / 3
a = 15
b = 15 - 3
b = 12
Answered by
Anonymous
the first of two films lasted 9 minutes less than twice as long as the second. the combined length of the two films plus a 5-minute break between them was 260 minutes. how long was the first film?
Answered by
Minecraft is Amazing
x + 2x - 9 + 5 = 260
3x - 4 = 260
3x = 264
x = 88
3x - 4 = 260
3x = 264
x = 88
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