can anyone please help me solve this step by step by using the quadratic formula..
-4t^2-9t-3=0
3 answers
see below
t = -b/2a +/- (1/2a) sqrt (b^2 - 4 a c)
a = 4
b = 9 Note = I multiplied both side by -1
c = 3
t = -9/8 +/- (1/8) sqrt(81 - 48)
t = -9/8 +/- (1/8)sqrt (33)
t = [ -9+sqrt(33) ]/8
or
t = [ -9-sqrt(33) ]/8
a = 4
b = 9 Note = I multiplied both side by -1
c = 3
t = -9/8 +/- (1/8) sqrt(81 - 48)
t = -9/8 +/- (1/8)sqrt (33)
t = [ -9+sqrt(33) ]/8
or
t = [ -9-sqrt(33) ]/8
DanH
I think you have a sign mistake
-b/2a = -(-9)/(-8) = -9/8
I think you have a sign mistake
-b/2a = -(-9)/(-8) = -9/8