Question
for a damped harmonic oscillation , the equation of motion is md^2x/dt^2+(gamma)dx/dt+kx=o with m=0.025kg,(gamma)=0.07kg/s and k=85N/m.
*calculate the period of motion
*number of oscillation in which its amplitude will become half of its initial value
*the number of oscillation in which its mechanical energy will drop to half of its intial value
*its relaxation time
*quality factor
*calculate the period of motion
*number of oscillation in which its amplitude will become half of its initial value
*the number of oscillation in which its mechanical energy will drop to half of its intial value
*its relaxation time
*quality factor
Answers
Related Questions
For a damped harmonic oscillation, the equation of motion is
0, 2
2
+ g + kx =
dt
dx
dt
d x...
A particle executes simple harmonic motion such that at t = 0 it is at the amplitude of oscillation...
The period of oscillation of a particle executing or undergoing simple harmonic motion is 45 sec if...
The period of oscillation of a particle executing simple harmonic motion is 4(22/7) seconds. If the...